Class name Subject Book title Chapter number Content Created at
Class VI Mathematics Ganita Prakash 5 Ans. 6. Q.4. Find the common factors of: a. 20 and 28 b. 35 and 50 c. 4, 8 and 12 d. 5, 15 and 25 Ans. a. Common factors of 20 and 28 = 1, 2, 4. b....
Class VI Mathematics Ganita Prakash 5 21 to 30: 8 Page No. 114 Figure it out Q.1. We see that 2 is a prime and also an even number. Is there any other even prime? Ans. No. Q.2. Look at ...
Class VI Mathematics Ganita Prakash 5 59 and 61, 71 and 73. Q.9 Identify whether each statement is true or false. Explain. a. There is no prime number whose units digit is 4. b. A produ...
Class VI Mathematics Ganita Prakash 5 55 Ans. Safe pairs are: 4 and 15, 18 and 29. Page no. 116 Q. Which of the following pairs of numbers are co-prime? a. 18 and 35 b. 15 and 37 c. 30 ...
Class VI Mathematics Ganita Prakash 5 3 ×3 ×3 1024 = 2 × 2 × 2 × 2 × 2 ×2 × 2 × 2 × 2 × 2 1331 = 11 × 11 × 11 1000 = 2 × 2 × 2 × 5 × 5 × 5 Q.2. The prime factorisation of a number has o...
Class VI Mathematics Ganita Prakash 5 Yes 343 = 7 × 7 × 7 216 = 2 × 2 × 2 × 3 × 3 × 3. Q.2. Is the first number divisible by the second? Use prime factorisation. a. 225 and 27 b. 96 and...
Class VI Mathematics Ganita Prakash 5 140 that are divisible by 8. Also find numbers between 1120 and 1140, and 3120 and 3140, that are divisible by 8. What do you observe? Ans. The num...
Class VI Mathematics Ganita Prakash 5 4-digit number divisible by 4 and also a palindrome: 9999 The smallest 4-digit number divisible by 4 and also a palindrome: 1001. Q.3. Explore and ...
Class VI Mathematics Ganita Prakash 5 Q.7. Write two numbers whose product is 10000. The two numbers should not have 0 as their unit digit. Ans. 10000 = 16 × 625.
Class VI Mathematics Ganita Prakash 6 PERIMETER AND AREA 6.1 Perimeter Do you remember what the perimeter of a closed plane figure is? Let us refresh our understanding! The perimeter of...
Class VI Mathematics Ganita Prakash 6 Thus, the length of the tape required = perimeter of the square = sum of the lengths of all four sides of the square = 1 m + 1 m + 1 m + 1 m = 4 m....
Class VI Mathematics Ganita Prakash 6 park of side 75 m. Solution Perimeter of the square park = 4 × length of a side = 4 × 75 m = 300 m. Distance covered by Usha in one round = 300 m. ...
Class VI Mathematics Ganita Prakash 6 along the rectangular 0 tracks as shown in the figure. Akshi runs along the 4 m 3 outer track and completes 5 rounds. Toshi runs along the inner tr...
Class VI Mathematics Ganita Prakash 6 If the total race is of 350 m, then we have to find out where the starting positions of the two runners should be on these two tracks so that they ...
Class VI Mathematics Ganita Prakash 6 and all five angles are equal), etc. Perimeter of an equilateral triangle We know that for any triangle its perimeter A is sum of all three sides. ...
Class VI Mathematics Ganita Prakash 6 Area of a rectangle = _______ Teacher’s Note Help students in recalling the method of finding the area of a rectangle and a square using grid paper...
Class VI Mathematics Ganita Prakash 6 16 sq m. Hence, the area of the four flower beds = 4 × 16 sq m = 64 sq m. Therefore,theareaoftheremainingpartofthelandis:areaofthecomplete land min...
Class VI Mathematics Ganita Prakash 6 E have the same area. You would have also figured out that Shape D can be exactly covered using Shapes C and E, which means Shape D has twice the a...
Class VI Mathematics Ganita Prakash 6 length 3. Count area? the squares and use them to estimate the area of the circular region. As you can see, circles can’t be packed tightly without...
Class VI Mathematics Ganita Prakash 6 area? Try this with more rectangles having different dimensions. You can check this for a square as well.  Can you draw any inferences from this ex...
Class VI Mathematics Ganita Prakash 6 of the areas of the rectangles AFED and BFEC = half of the area of rectangle ABCD. Conclusion ____________________________________________________ ...
Class VI Mathematics Ganita Prakash 6 ____ ft) 5 Area = ____ t T × i 0 e Master Bedroom t t (15 ft × 15 ft) ) Area=225 sq ft Kitchen (15 ft × 12 ft) Area = 180 sq ft f Small Bedroom (15...
Class VI Mathematics Ganita Prakash 6 cm 4 cm 15 cm 42 sq cm 6 cm 38 sq cm 5 cm 5 cm 18 sq cm 60 sq cm Reprint 2026-27 Perimeter and Area Figure it Out 1. Give the dimensions of a recta...
Class VI Mathematics Ganita Prakash 6 into more generalshaped rectangles and triangles whose areas can be calculated. Reprint 2026-27 CHAPTER 6 — SOLUTIONS Perimeter and Area Section 6....
Class VI Mathematics Ganita Prakash 6 (c) Length of each side of regular hexagon = 6 cm [1] Q.6. A farmer has a rectangular field having length 230 m and breadth 160 m. He wants to fenc...