| Class XI |
Psychology |
Introduction to Psychology |
4 |
have been given pictures for to pictures have difficulty in the interpretation identification of objects and interpretation of of actions or events... |
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| Class XI |
Psychology |
Introduction to Psychology |
4 |
contours. The most primitive form of organisation takes place in the form of figure-ground segregation. • Gestalt psychologists have identified sev... |
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| Class XI |
Psychology |
Introduction to Psychology |
4 |
children. Let the visually challenged children feel by touching the toy model for some time. Ask the children to describe the model. Show the same ... |
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| Class XI |
Psychology |
Introduction to Psychology |
5 |
Learning Chapter Afterreadingthischapter,youwouldbeableto • describe the nature of learning, • explain different forms or types of learning and the... |
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| Class XI |
Psychology |
Introduction to Psychology |
5 |
and characterised as a psychological process. Second, an account is presented that explains how one learns. A number of learning methods that accou... |
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| Class X |
Science |
Science |
11 |
6 Wires crossing without joining 174 Science Reprint 2026-27 7 Electric bulb or 8 A resistor of resistance R 9 Variable resistance or rheostat or 1... |
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| Class X |
Science |
Science |
11 |
in Fig. 11.3. Thus, V/I is a constant ratio. In 1827, a German physicist Georg Simon Ohm (1787–1854) found out the relationship between the current... |
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| Class X |
Science |
Science |
11 |
is often used to change the resistance in the circuit. We will now study about electrical resistance of a conductor with the help of following Acti... |
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| Class X |
Science |
Science |
11 |
conductor is retarded by its resistance. A component of a given size that offers a low resistance is a good conductor. A conductor having some appr... |
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| Class X |
Science |
Science |
11 |
the same material and of the same length is used in the circuit. A change in ammeter reading is observed when a wire of different material of the s... |
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| Class X |
Science |
Science |
11 |
× 10–8 –8 Aluminium 2.63 × 10 Tungsten 5.20 × 10–8 Nickel 6.84 × 10–8 –8 Iron 10.0 × 10 Chromium 12.9 × 10–8 Mercury 94.0 × 10–8 –6 Manganese 1.84 ... |
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| Class X |
Science |
Science |
11 |
increased to 120 V the current is given by V 120 V current = = = 8 A . R 15 Ω The current through the heater becomes 8 A. Example 11.5 Resistance o... |
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| Class X |
Science |
Science |
11 |
Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to hal... |
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| Class X |
Science |
Science |
11 |
to anywhere in between the resistors. Note the ammeter reading each time. ■ Do you find any change in the value of current through the ammeter? You... |
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| Class X |
Science |
Science |
11 |
the circuit. The current through each resistor is also I. It is possible to replace the three resistors joined in series by an equivalent single re... |
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| Class X |
Science |
Science |
11 |
= 20 Ω × 0.25 A = 5 V; and, that across the conductor, V2= 4 Ω × 0.25 A = 1 V. Suppose that we like to replace the series combination of electric l... |
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| Class X |
Science |
Science |
11 |
the voltmeter across each individual resistor (see Figure 11.10 Fig. 11.11). Electricity 185 Reprint 2026-27 ■ Take out the plug from the key. Remo... |
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| Class X |
Science |
Science |
11 |
the current in the resistors, we use Ohm’s law. The current I ,1through R1= V/ R 1 I = 12 V/5 Ω = 2.4 A. 186 Science Reprint 2026-27 The current I ... |
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| Class X |
Science |
Science |
11 |
throughout the electric circuit. Thus it is obviously impracticable to Figure 11.12 connect an electric bulb and an electric heater in series, beca... |
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| Class X |
Science |
Science |
11 |
coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω? 11.7 HEA TING EFFECT OF ELECTRIC CURRENT We know that a battery or a cell is a source of electrical energ... |
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| Class X |
Science |
Science |
11 |
happens to this energy expended by the source? This energy gets dissipated in the resistor as heat. Thus for a steady current I, the amount of heat... |
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| Class X |
Science |
Science |
11 |
resistor as I = √(H/Rt) = √[100 J/(4 Ω × 1 s)] = 5 A Thusthepotentialdifferenceacrosstheresistor, V [fromEq.(11.5)]is V = IR = 5 A × 4 Ω = 20 V. El... |
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| Class X |
Science |
Science |
11 |
common application of Joule’s heating is the fuse used in electric circuits. It protects circuits and appliances by stopping the flow of any unduly... |
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| Class X |
Science |
Science |
11 |
1 watt of power is used for 1 hour. The commercial unit of electric energy is kilowatt hour (kW h), commonly known as ‘unit’. 1 kW h = 1000 watt × ... |
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| Class X |
Science |
Science |
11 |
of flow of electrons. ■ The SI unit of electric current is ampere. ■ To set the electrons in motion in an electric circuit, we use a cell or a batt... |
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